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3 years ago

What factors decrease the transfer of thermal energy? ASAP

Chemistry

2 answers:

poizon [28]3 years ago

7 0

Answer:

What 3 factors influence the amount of thermal energy in an object, and how do they each affect it? Mass, temperature, and phase. More mass, more Thermal Energy. Higher temperature, more Thermal Energy.

ASAP=abbreviation. As soon as possible. 'fill in your form and send it to us ASAP' More example sentences.

gtnhenbr [62]3 years ago

6 0

Mass tempature phase , thermal and plenty more

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Can anyone give the ans please ...

Burka [1]

Answer:

..................mm.m

8 0

4 years ago

When hydrochloric acid is poured over potassium sulfide, 43.7 mLmL of hydrogen sulfide gas is produced at a pressure of 758 torr

kvasek [131]

Answer:

0.196 grams of K2S reacted

Explanation:

When hydrochloric acid is poured over potassium sulfide, 43.7 mLmL of hydrogen sulfide gas is produced at a pressure of 758 torrtorr and 26.0 ∘C

How much potassium sulfide has reacted in grams?

Step 1: Data given

Volume of hydrogen sulfide (H2S) produced = 43.7 mL

Pressure = 758 torr = 758/760 = 0.9973684 atm

Temperature = 26.0 °C = 273 + 26 = 299 K

Step 2: The balanced equation

2 HCl + K2S → H2S + 2 KCl

Step 3: Calculate moles H2S

p*V = nRT

n = (pV)/(RT)

⇒ with n= the number of moles of H2S

⇒ with p = the pressure = 0.9973684 atm

⇒ with V = the volume of the gas = 43.7 mL = 0.0437 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = The temperature = 26°C = 299 Kelvin

n = (0.9973684 * 0.0437)/ (0.08206*299)

n = 0.001776 moles H2S

Step 4: calculate moles of K2S

For 2 moles HCl we need 1 mol K2S to produce 1 mol H2S and 2 moles KCl

For 0.001776 moles H2S produced, we need 0.001776 moles K2S

Step 5: Calculate mass of K2S

Mass K2S = moles K2S * molar mass K2S

Mass K2S = 0.001776 moles * 110.26 g/mol

Mass K2S = 0.196 grams K2S

0.196 grams of K2S reacted

6 0

3 years ago

Potassium hydroxide, also known as lye, dissociates into metal and hydroxide ions in water.

lesya692 [45]

Answer:

strong acid and weak base

Explanation:

#carryonlearning

5 0

3 years ago

BRAINLIESTTT ASAP!!! PLEASE HELP ME :)

Ahat [919]

Every science experiment should follow the basic principles of proper investigation so that the results presented at the end are seen as credible.

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Law Formation.

6 0

4 years ago

Read 2 more answers

What is the freezing point of a solution that contains 12.0 g of glucose (C6H12O6) in 50 g of acetic acid (CH3COOH). For acetic

sergij07 [2.7K]

Answer:

T = 11.4°C

Explanation:

Given that:

weight of solute w (glucose) = 12 g

weight of solvent W (acetic acid) = 50 g

Molar depression constant of solvent (Kf)= 3.90°C/m

Temperature of solvent freezing point T₀ = 16.6°C

Temperature of solution freezing point Tₓ = (T₀ -T) = ???

Molar mass of solute (glucose) = 180.2 g/mol

Using the expression;

(T₀ -T) = $\frac{1000*k_f*w}{MM*W}$

$(16.6-T)=\frac{1000*3.90*12}{180.2*50}$

$(16.6-T)=\frac{46800}{9010}$

$(16.6-T) = 5.194^0C$

$(16.6-T) = 5.2^0C$

-T = -16.6 °C + 5.2 °C

- T = -11.4°C

T = 11.4°C

∴ The freezing point of the solution is said to be = 11.4°C

6 0

4 years ago