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3 years ago

What factors decrease the transfer of thermal energy? ASAP

Chemistry

2 answers:

poizon [28]3 years ago

7 0

Answer:

What 3 factors influence the amount of thermal energy in an object, and how do they each affect it? Mass, temperature, and phase. More mass, more Thermal Energy. Higher temperature, more Thermal Energy.

ASAP=abbreviation. As soon as possible. 'fill in your form and send it to us ASAP' More example sentences.

gtnhenbr [62]3 years ago

6 0

Mass tempature phase , thermal and plenty more

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Unemployment rate varies according to such factors as

sineoko [7]

I’m pretty sure the answer is A.

3 0

3 years ago

How many total chlorine atoms are in the formula 4NaCl

postnew [5]

Answer:

4 Chlorine atons

Explanation:

4 molecules of NaCl

In NaCl we have only 1 atom of Cl

Therefore in 4 molecules, we have 4 atoms of Cl.

please mark brainliest

7 0

3 years ago

Balance the following equation _NaOH (aq) + _HNO3 (aq)> _NaNO3 (aq)+ _H2O (1)

Vlada [557]

Its already balanced, no balancing required

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3 years ago

Hydrazine, , emits a large quantity of energy when it reacts with oxygen, which has led to hydrazine used as a fuel for rockets:

Tcecarenko [31]

Answer:

$1.25~mol~H_2O$ and $0.627~mol~N_2$

Explanation:

Our goal for this question is the calculation of the number of moles of the molecules produced by the reaction of hydrazine ( $N_2H_4$ ) and oxygen ( $O_2$ ). So, we can start with the reaction between these compounds:

$N_2H_4~+~O_2~->~N_2~+~H_2O$

Now we can balance the reaction:

$N_2H_4~+~O_2~->~N_2~+~2H_2O$

In the problem, we have the values for both reagents. Therefore we have to calculate the limiting reagent. Our first step, is to calculate the moles of each compound using the molar masses values (32.04 g/mol for $N_2H_4$ and 31.99 g/mol for $O_2$ ):

$20.1~g~N_2H_4\frac{1~mol~N_2H_4}{32.04~g~N_2H_4}=0.627~mol~N_2H_4$

$20.1~g~O_2\frac{1~mol~O_2}{31.99~g~O_2}=0.628~mol~O_2$

In the balanced reaction we have 1 mol for each reagent (the numbers in front of $O_2$ and $N_2H_4$ are 1). Therefore the smallest value would be the limiting reagent, in this case, the limiting reagent is $N_2H_4$ .

With this in mind, we can calculate the number of moles for each product. In the case of $N_2$ we have a 1:1 molar ratio (1 mol of $N_2$ is produced by 1 mol of $N_2H_4$ ), so:

$0.627~mol~N_2H_4\frac{1~mol~N_2}{1~mol~N_2H_4}=~0.627~mol~N_2$

We can follow the same logic for the other compound. In the case of $H_2O$ we have a 1:2 molar ratio (2 mol of $H_2O$ is produced by 1 mol of $N_2H_4$ ), so:

$0.627~mol~N_2H_4\frac{2~mol~H_2O}{1~mol~N_2H_4}=~1.25~mol~H_2O$

I hope it helps!

4 0

4 years ago

A student has a remote control for a television. The student points the

Gwar [14]

Answer:

The remote control sends low-energy infrared radiation to a light detector on the front of the television

Explanation:

The signal between a remote control and the TV controls consists of pulses of infrared light, which is invisible to the human eye

3 0

3 years ago