0.52kg = 520g
520g x 0.35 = 182g
182 x 6.022x10^23 = 1.096004E26
1.096004E26 / 107.8 = 1.0167012987E24 atoms
Answer:
there are 6 significant figures in 107.051
Answer:
1 mol SO2 contains 6.0213*10^23 molecules
6.023*10^24 molecules = 10 mol SO2
Equation
S(s) + O2(g) → SO2(g)
1 mol S reacts with 1 mol O2 to prepare 1 mol SO2
To prepare 10 mol SO2 you require : 10 mol S plus 10 mol O2
And that is the answer to the question
If you want a mass :
Molar mass S = 32 g/mol You require 10 mol = 320 g
Molar mass O2 = 32 g/mol :You require 10 mol = 320 g
It should be the digestive system as it absorbs the nutrients of the food into your body.
