Question

Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is measured in meters, and the variable t is measured in seconds. The equation describing the graph of the position of the first object with respect to time is d = 2. 5t 2. 2. The graph of the position of the second object is a parallel line passing through (t = 0, d = 1). What is the equation of the second graph? A. D = 2. 5t 1 B. D = t 2. 5 C. D = -0. 4t 1 D. D = 2. 5t 3. 2.

Answer 1

The equation of second graph is  $d = 2.5 t + 1$

We have given the linear equation is

$d = 2.5 t +2.2,$

If the graph of the position of the second object is parallel to

$d = 2.5 t +2.2,$

What is the  form of linear equation?

The equation of slope intercept form is

$d=mt+b$

compare the given equation with the slope intercept form

we get  m = 2.5

t = 0, d = 1

1 = 2.5 · 0 + b

b = 1

Therefore,the equation of second graph is  $d = 2.5 t + 1$

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