Let x = the number.
"increased by" tells you we are adding.
"twice a number" tells you 2 times a number.
16 + 2x = - 24
Subtract 16 from both sides so that we have the variable on one sides and the constants on the other.
2x = - 24 - 16
2x = - 40
Divide by 2 to isolate the variable.
x = - 40/2 = - 20
Your solution is - 20.
To check your answer, plug in.
16 + 2(-20) = - 24
16 - 40 = - 24
- 24 = - 24
7900 should be the answer, is there any options?
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
I’m a bit confused by the choices you have been given. Are there any other options? If not, I would choose (5.3,9.8) as 9.8 is correct
