San Antonio to El Paso
= 558 mi
--------------------
Lubblock to Abilene 165 mi
165 / 55 = 3 hours
you must be there in 2 1/2 hours
so
answer is No
321 times 23 is 7,383
3,829 divided by 1,221 is (rounded to the nearest hundredth) 3.14
(the real number was: 3.13595414)
Answer: The first one is Commutative Property
The second one is associative property
Step-by-step explanation:
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:

In this problem, we have that:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So







A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07