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Molodets [167]
2 years ago
5

Subtract 4x^2-5xy+9y^2 from 6x^2+4xy-7y^2

Mathematics
2 answers:
just olya [345]2 years ago
6 0

Answer:

ok i got your answer you hath to take out all those x,y s and you will get this 4^{2}-5+9^{2}-6^{2}+4-7^{2}equals 11

Step-by-step explanation:

HOPE I HELPED PLZ GIVE ME A THANKS

mixer [17]2 years ago
5 0

2x2 - 16y2 + 9xy

(the 2 to the right of the x and y are small numbers i forgot what dey are called lol)

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3 years ago
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Rzqust [24]
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8 0
3 years ago
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san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

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\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

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mote1985 [20]

Answer:

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Step-by-step explanation:

idrk

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