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Ilya [14]
2 years ago
5

How is a fraction related to its simplified form brainpop

Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0

Answer:

Simplifying a fraction implies reducing a fraction to its lowest form. A fraction is in its simplest form if its numerator and denominator have no common factors except 1. The simplest form of a fraction is equivalent to the given fraction.

Step-by-step explanation:

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What is the slope of the line passing through (1, 2) and (3, 8)?
Alexeev081 [22]
Slope = Change in y / Change in x

= 8 - 2 / 3 - 1

= 6 / 2

= 3
3 0
3 years ago
Read 2 more answers
Michelle is checking a division problem by doing the following: 128
MrRa [10]
899/7.....if u plug this into a calculator u will get 128.(and a bunch of decimal numbers).....but u have the whole number 128....so 128 x 7 = 896 + 3 = 899

so the answer to this problem is basically : 899/7 = 128 remainder 3
6 0
3 years ago
Help me please . quick :)
ycow [4]

Answer:

x= 1

QS = 10 cm

QRS = 40cm

Step-by-step explanation:

4x + 1 = 5x

x= 1 cm

QS = 4x + 1 + 5x

= 9x + 1

= 9 + 1

= 10cm

QRS perimeter

QS + RQ + RS but ( RQ = RS)

= 10 + 15 + 15

= 40cm

3 0
3 years ago
Estimate the difference of 4/5 - 1/2
torisob [31]
3/10 is the answer to 4/5-1/2
5 0
3 years ago
Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5​
Bond [772]

Answer:

The solution to the equation system given is:

  • <u>x = 2</u>
  • <u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

  1. 2x + 3y = 1
  2. 3x + y = 5​

Following Crammer's Rule, we have the matrix form:

\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Now we solve using the determinants:

x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2

y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

  • 2x + 3y = 1
  • 2(2) + 3(-1)= 1
  • 4 - 3 = 1
  • 1 = 1

And, with the second equation:

  • 3x + y = 5​
  • 3(2) + (-1) = 5
  • 6 - 1 = 5
  • 5 = 5

 

4 0
3 years ago
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