Actually I don't know the answer but what I thing is none of the above.
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
Please give me Brainliest
512x^3 would be the answer
Answer:
because The perimeter of a rectangular playground can be no greater than 120 meters, The width of the playground cannot exceed 22 meters
=> the length of the playground cannot exceed: (120/2)-22= 38(meters)
Step-by-step explanation:
Answer:
$20d = c
Step-by-step explanation:
Since the cost is $20 per day, $20d ($20 for how many days) would be the start of the equation.
C = cost, and $20d will determine the cost, so $20d = c
is your final answer/equation.
Cheers!
