What operation is shown when there is a number sitting infront of a variable?
2 answers:
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The <u>correct diagram</u> is attached.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.
The values of x are
1. x = 32°,
2. x = 15°,
3. x = 49°,
4. x = 65°,
Explanation:
- The angle made by any right angle is 90° and the angle made by a straight line is 180°. These are the main equations required to solve the values of x. The first 2 are right angles and the last 2 are straight lines. So the sum of the components within that right angle is 90° and for a straight line is 180°.
- For diagram 1; 2x° + x° - 6° = 90°, 3x° = 90° + 6° = 96°, x =
= 32°.
- For diagram 2; 4x° + 3° + x° + 12° = 90°, 5x° = 90° - 15° = 75°, x =
= 15°.
- For diagram 3; x° + 33° + 2x° = 180°, 3x° = 180° - 33 = 147°, x =
= 49°.
- For diagram 4; 2x° + 1° + x° - 16° = 180°, 3x° = 180° + 15° = 195°, x =
= 65°.