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Dima020 [189]
2 years ago
7

What are the solutions to 9x^2-63x=0

Mathematics
1 answer:
wariber [46]2 years ago
7 0

Answer: x = 0 and x = 7

Step-by-step explanation:

9x^2 - 63x = 0.

We can factor out 9x from both terms on the left side:

9x(x - 7) = 0.

To be equal to 0, one of the terms has to be 0.

Therefore, either 9x = 0 or x - 7 = 0.

First, we solve the case where 9x = 0.

Then, x = 0.

Second, we solve the case where x - 7 = 0.

We add 7 to both sides:

So, x = 7

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Sum of the interior angles of any triangle equal 180 degrees .

Thus ;

(3x + 10) + (5x + 16) + 90 = 180 \\

Subtract sides 90

(3x + 10) + (5x + 16) + 90 - 90 = 180 - 90 \\

Simplification

(3x + 10) + (5x + 16) = 90

3x + 10 + 5x + 16 = 90

Collect like terms

3x + 5x + 10 + 16 = 90

8x + 26 = 90

Subtract sides 26

8x + 26 - 26 = 90 - 26

8x = 64

Divide sides by 8

\frac{8x}{8}  =  \frac{64}{8}  \\

x = 8

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So ;

The angle marked as 3x + 10 would measure 34° degrees.

3(8) + 10 = 24 + 10 = 34

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And ;

The angle marked as 5x + 16 would measure 56° degrees.

5(8) + 16 = 40 + 16 = 56

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