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viva [34]
3 years ago
15

A group of 8 children and 10 adults ate going to a movie. Child tickets cost $2 and adults tickets cost $4. How much will the mo

vie tickets cost in all ?
Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

56$

Step-by-step explanation:

8*2=16

10*4=40

16+40=56

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R --> 2 P. Initially you start off with 0.5 M reactants and let the reaction run to equilibrium and calculate the equilibrium
Anit [1.1K]

Answer:

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

\frac{C^{c}D^{d}  }{A^{a}B^{b} }

K is a constant so it won't change the value. Instead, the values of C and D are going to change.  The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

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2 years ago
Can you solve this equation?​
Leya [2.2K]

Answer:

10 + 10 + 10 = 30 \\ 10 + 5 + 5 = 20 \\ 5 + 4 + 4 = 13 \\ 10 + 5 + 2 = 17

5 0
3 years ago
Read 2 more answers
One half of the sum of a number and 10
garri49 [273]

Let's assume the number be x.

So, sum of a number and 10 can be written as x+10.

Now the given statement is "One half of the sum of a number and 10 ".

So, one half of x+10 can be written as \frac{1}{2} (x+10)

6 0
3 years ago
One of our brainliest, Konrad509, made this:
Reil [10]

\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x

A=10, B=11, C=12, etc.

\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2

121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that x\in\mathbb{N}. Moreover we can deduce that x\geq19 since there is J and J=19.

After you succesfully solve it, you should get the answer x=20.

7 0
3 years ago
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