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2 years ago

Y =400(.99)x growth or delay?

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

3 0

Answer:

Delay

Step-by-step explanation:

Because you are multiply x into 0.99, every time the multiplication takes place it will only become 99% of the value of the product of x and 400.

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2 years ago

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Sketch the plane representing -2x²=-8

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3 years ago

F(x)=2x+6 what is the value of f(7)

Deffense [45]

F(7)= (2x7) + 6
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3 years ago

A boat leaves the dock and travels 9 miles due south, then 12 miles due west.

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3 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago