Answer:

Step-by-step explanation:
There are no given values, therefore we can't determine a definite answer. However, we are able to simplify the expression.
As we all know that any variable or number to the power of 0 is equal to 1. This means that
.
We also know that a negative power can bring the variable down and make it a fraction. This means that 
Now that we got these two sorted we are able to write it in a simplified form.
Answer: 
Answer:
D.mode
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer: N = 143
Discussion:
This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers: 11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of 3 consecutive primes. I went back to my list of primes, added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on 43, 47, and 53!
43 + 47 + 53 = 143 !
Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.
Thank you,
MrB
Part A: This data does represent a function because no value of x is repeated.
Part B: If x = 6 for the relation f(x) = 7x - 15, then f(x) will equal 27. The function f(x) = 7x - 15 will have the greater value
Part C: If f(x) is equal to 6 then x will equal 3