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3 years ago

Pls answer I will follow you if u do answer

Mathematics

1 answer:

Marianna [84]3 years ago

3 0

Answer:

The answer is 113

Step-by-step explanation:

6^2 + 7(3^2 + 8 - 6)

36 + 7(9 + 8 - 6)

36 + 7(11)

36 + 77

113

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Acar can travel 25 miles per gallon. Approximately how many gallons of fuel will the car need to travel 30

FrozenT [24]

Answer:

The gallons of fuel car need to travel 30 km is <u>0.75</u> approximately .

Step-by-step explanation:

Given:

The car can travel 25 miles per gallon. (1 mile = 1.6 km)

Now, we need to convert 25 miles into km .

25 miles = 25 × 1.6 km

= 40 km

So, the car can travel 40 km per gallon.

Then, we find out in 1 km how many gallons are used:

$40 km = 1 gallons$

$1\ km = \frac{1}{40}\ gallons$

$1\ km = 0.025\ gallons$

Now, we find out how much gallons of fuel will the car need to travel 30 km:

Gallons of fuel the car need to travel 30 km = $30\times 0.025$

= $0.75 gallons$ .

Therefore, the gallons of fuel car need to travel 30 km is 0.75 approximately.

6 0

3 years ago

An oarsman can row his boat 3 mph in still water. He sets out on the Illinois River, which flows at 5 mph. We are interested in

Artyom0805 [142]

Answer:

The speed from the observer is 8 mph.

Step-by-step explanation:

When the boat is going downstream with full force, its speed will be the one the oarsman can row on still water added by the flow of the river. In this case he can row the boat at speed of 3 mph, while the stream is 5 mph, so the speed from the observer standpoint is:

$speed = 3 + 5\\speed = 8 \text{ mph}$

The speed from the observer is 8 mph.

4 0

3 years ago

Please help me with #'s 5&6

Fynjy0 [20]

$5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}$

$6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}$