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Natalija [7]
3 years ago
5

Elise gathered details about her finances to create financial assets and liabilities record. which represents one of her liabili

ties ?
a ( her checking account balance of $2827
b ( her jewelry valued at $1375
c ( balance of $9460 on her auto loan
d ( rental property valued at $132,000
Mathematics
1 answer:
12345 [234]3 years ago
5 0
Liabilities is basically money owed.....so thats gonna be C. the balance of 9460 on her auto loan
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-18-12+(24/-8)-2(-15+10)
tigry1 [53]

Answer:

-17

Step-by-step explanation:

-18-12+(24/-8)-2(-15+10)

-18-12(-3)-2(-5)

-18-9-2(-5)

-27-2(-5)

-27+10

-17

I hope this helps! Please mark as brainliest! :D Good Luck! :)

3 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!
olga55 [171]
11/5x-1 this should be the answer
4 0
3 years ago
Help??? There's a photo.
Nataly_w [17]
I believe the answer is C
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%284v%5E%7B-3%7D%20%29%5E3%2F3v%5E%7B-8%7D" id="TexFormula1" title="(4v^{-3} )^3/3v^{-8}" alt=
Svet_ta [14]

Answer:

=\frac{64}{3v}

Step-by-step explanation:

One is given the following equation:

\frac{(4v^-^3)^3}{3v^-^8}

Simplify the numerator, remember to raise every number inside the parenthesis to the exponent outside of the parenthesis. Bear in mind, an exponent raised to another exponent is equal to the exponent times the exponent it is raised to. Then simplify by multiplying the number by itself the number of times that the exponent indicates.

\frac{(4v^-^3)^3}{3v^-^8}

=\frac{4^3(v^-^3)^3}{3v^-^8}

=\frac{4^3v^-^9}{3v^-^8}

=\frac{64v^-^9}{3v^-^8}

Bring the variable (v) in the denominator (value under the fraction bar) to the numerator (value ontop of the fraction bar) by multiplying its exponent by (-1). This can be done simply because all operations in this equation are multiplication or division, remember, an exponent is another form of multiplication.

=\frac{64v^-^9}{3v^-^8}

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

Simplify, remember, multiplying two numbers with the same base that have an exponent is the same as adding the two exponents,

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

=\frac{(64v^-^9)(v^8)}{3}

=\frac{64v^-^9^+^8)}{3}

=\frac{64v^-^1}{3}

Now bring the variable to the denominator so that there are no negative exponents. Use a similar technique that was used to bring variables with exponents to the numerator.

=\frac{64v^-^1}{3}

=\frac{64}{3(v^(^-^1^)^(^-^1^))}

=\frac{64}{3v^1}

=\frac{64}{3v}

5 0
3 years ago
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