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2 years ago

Select the correct answer.

Mathematics

1 answer:

NeX [460]2 years ago

8 0

Answer:

C. Wright Mills

Step-by-step explanation:

was the American sociologist who strongly criticized the structural functionalist approach to sociology.

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Find the HCF and LCM of 126 and 234?

Leni [432]

Answer:

Below in bold.

Step-by-step explanation:

Find the prime factors:-

126 = 2 * 3 * 3 * 7

234 = 2 * 3 * 3 * 13

So the GCF = 2 * 3 * 3 = 18.

The LCM = 2 * 3 * 3 * 7 * 13

= 1638.

8 0

2 years ago

For the following exercises, find (f ∘ g)(x) and (g ∘ f)(x) for each pair of functions.

Rufina [12.5K]

Answer:

The value of $(f \circ g)(x)$ is 17-18x and $(g \circ f)(x)$ is -7-18x.

Step-by-step explanation:

It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$ .

To find $(f \circ g)(x)$ , substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$ , substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$

5 0

2 years ago

If a track is 400 meters around, how many laps around the track would it take to run 3.1 miles? Round to the nearest tenth. (Hin

zaharov [31]

Answer:

3200 meters

Step-by-step explanation:

because it is

4 0

2 years ago

If a case of chips has 27 bags in it. How many cases would they need for 410 bags of chips?

kodGreya [7K]

Answer:

they would need 15 cases for 410 bag of chips

Step-by-step explanation:

410/7= about 15

3 0

2 years ago

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$

Step 4: Using fraction rule:

$$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}$

$$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}$

Cancel the common factor r and t², we get

$$=\frac{64 r^{2} \cdot 9 }{16 \cdot 15 t^2 }$

Cancel the common factors 16 and 3 on both numerator and denominator.

$$=\frac{4 r^{2} \cdot 3 }{ 5 t^2 }$

$$=\frac{12 r^{2} }{ 5 t^2 }$

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2} }{ 5 t^2 }$

The simplified fraction is $\frac{12 r^{2} }{ 5 t^2 }$ .

5 0

3 years ago