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The only ordered pair that is a solution to the given system of equations is (-2, -6)
<h3>System of Linear Equations </h3>From the question, we are to determine if each ordered pair is a solution to the given system of equations
The given system of equations is
-9x + 2y = 6
5x - 3y = 8
- For (7, 9)
That is,
x = 7, y = 9
Putting the values into the first equation
Is -9(7) + 2(9) = 6
-63 + 18 = 6
-45 ≠ 6
Thus, (7,9) is not a solution
- For (0, 3)
That is,
x = 0, y = 3
Putting the values into the first equation
Is -9(0) + 2(3) = 6
0 + 6 = 6
6 = 6
The ordered pair satisfies the first equation
Testing for the second equation
Is 5(0) - 3(3) = 8
0 - 9 = 8
-9 ≠ 8
Thus, (0, 3) is not a solution
- For (5, -4)
That is,
x = 5, y = -4
Putting the values into the first equation
Is -9(5) + 2(-4) = 6
-45 - 8 = 6
-53 ≠ 6
Thus, (-5,4) is not a solution
- For (-2, -6)
That is,
x = -2, y = -6
Putting the values into the first equation
Is -9(-2) + 2(-6) = 6
18 - 12 = 6
6 = 6
The ordered pair satisfies the first equation
Testing for the second equation
Is 5(-2) -3(-6) = 8
-10 + 18 = 8
8 = 8
The ordered pair satisfies the second equation
∴ The ordered pair that is a solution to the system of equations is (-2, -6)
Hence, the only ordered pair that is a solution to the given system of equations is (-2, -6)
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If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:
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