Select the correct answer. Which statement is correct with respect to f(x) = -3|x − 1| + 12?

Some help fast ASAP for 15pts

cupoosta [38]

Step-by-step explanation:

Ef

2×9+2

=20

Ab

2×20-20

=20

3 0

3 years ago

What is the value of A?<br> -3x<br> -3x²<br> -5x<br> –5x²

frosja888 [35]

Answer:

i need to see all the problem

8 0

3 years ago

a theater has 30 rows with 27 seats in the first row, 31 in the second row, 35 in the third row, and so forth. How many seats ar

mrs_skeptik [129]

Answer:

Question relates to a Arithmetic Sequence {30,32,34...} where d = 2

and the terms are the enumber of seats in each row.

S%5Bn%5D=%28n%2F2%29%282%2Aa%5B1%5D%2B+%28n-1%29d%29 |Sum of the seats in the 26 rows.

S%5B26%5D=%2826%2F2%29%282%2A30%2B+%2825%292%29 = 1430 seats in the ALL 26 rows

Step-by-step explanation:

7 0

3 years ago

Without graphing, write an equation of a line that is steeper than y=1/3x. Write the equation in the comment bellow and explain

FrozenT [24]

The gradient of a line depends on how steep it is. The gradient of y=1/3x is 1/3 so you can use any other number that is higher than 1/3 eg y=2

8 0

4 years ago

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F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?

Ray Of Light [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

$\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)
\\\\\\
f(1x+4)=(1x+4)^2-3(1x+4)-2
\\\\\\
f(x+4)=x^2+8x+16-3x-12-2
\\\\\\
f(x+4)=x^2-5x+2\impliedby g(x)$

8 0

3 years ago

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