Notice that the 2 expressions have 2 common terms.
(r-s) is just (s-r) times (-1)
similarly
(t-s) is just (s-t) times (-1)
this means that :
(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)
the 2 minuses in the first multiplication cancel each other so we have:
-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)
Answer:
d)<span>2(s-r) (t-s) </span>
Answer: 25
Step-by-step explanation: got it wrong and got the answer Took 1 for the team
5*6=30
and 6*5=30
basically we have to take Lcm of 5 and 6=30
30th day they both will be together
For the first problem the answer is -5/2
2x−7+10=−2
Step 1: Simplify both sides of the equation.
2x−7+10=−2
2x+−7+10=−2
(2x)+(−7+10)=−2
(Combine Like Terms)
2x+3=−2
Step 2: Subtract 3 from both sides.
2x+3−3=−2−3
2x=−5
Step 3: Divide both sides by 2.
2x/2=−5/2
x=−5/2
Answer:
x= -5/2
Answer: Reformatting the input :
Changes made to your input should not affect the solution:
(1): "y3" was replaced by "y^3". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(23x2 • y3) - 5
STEP
2
:
Trying to factor as a Difference of Cubes
2.1 Factoring: 8x2y3-5
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : 8 is the cube of 2
Check : 5 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Final result :
8x2y3 - 5
