What is the slope of the line in the following graph? 1. 1/3 2. 1/2 3. 2 4. 3

olga_2 [115]

Answer : -4
Explanation:

7 0

3 years ago

A survey was conducted among 100 students of age groups 7−12 years and 13−18 years to find their favorite book genre. The studen

sukhopar [10]

The correct answer is C. 49.

Remember that there are 100 students divided into 7-12 and 13-18 age group. So there should be 50 for each. The table should go like this:

7-12 age group

23 adventure or biography

27 - detective

so you just have to subtract 50 from 23, which makes it 27. The remaining belongs to the 13-18 age group.

13-18 age group

1 - detective

49 - adventure or biography.

6 0

3 years ago

Read 2 more answers

Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 3000

defon

Answer:

a) 80
b) 56

Step-by-step explanation:

a) Calculate the volume of the the cup using volume of cylinder equation: $V = \pi r^{2} h$

Where V = Volume, r=radius, and h=height. Your answer should be in cubic inches ( $in^3$ ).
You're given diameter, so use equation $d/2 = r$ to find radius.
Substituting these equations will give you: $V = \pi (d/2)^2 h$
However, the given volume of the sink is 3000 $\pi$ , meaning that you should modify your results to match this value. Do not substitute $\pi$ for 3.14..., leave it as a symbolic value. Your final V of the cup should = 37.5 $\pi$
Divide the volume of the sink by the volume of the cup. This number will be the amount of cups needed to empty it. In equation form:
$Vsink / V cup =$ # of cups.
Note the the $\pi$ will cancel each other out, so there's not need to factor that in.
b) Repeat the steps above with the new d (diameter) value.

5 0

3 years ago

Of all the registered automobiles in a city, 12% fail the emissions test. Fourteen automobiles are selected at random to undergo

postnew [5]

Answer:

a) 0.1542

b) 0.7685

c) 0.2315

d) No, it is not unusual

Explanation:

The procedure to make the test meets the requirements of binomial experiments because:

there are two possible mutually exclusive outputs: fail the test, or pass the test.
the probability of each event remains constant during all the test (p=12% = 0.12, for failing the test, and 1-p = 88% = 0.88, for passing the test)
each trial (test) is independent of other trial.

Solution

(a) Find the probability that exactly three of them fail the test.

You want P(X=3)

Using the equation for discrete binomial experiments, the probability of exactly x successes is:

$P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}$

Substituting C(n,x) with its developed form, that is:

$P(X=x)=\dfrac{n!}{x!\cdot (n-x)!}\cdot p^x\cdot (1-p)^{(n-x)}$

Thus, you must use:

x = 3 (number of automobiles that fail the emissions test)
n = 14 (the number of automobiles selected to undergo the emissions test),
p = 0.12 (probability of failing the test; this is the success of the variable on our binomial experiment)
1 - p = 0.88 (probability of passing the test; this is the fail of the variable on our binomial experiment)

$P(X=3)=\dfrac{14!}{3!\cdot (14-3)!}\cdot 0.12^3\cdot 0.88^{11}=0.1542$

(b) Find the probability that fewer than three of them fail the test.

The probability that fewer than three of them fail the test is the probability that exactly 0, or exactly 1, or exactly 2 fail the test.

That is: P(X=0) + P(X=1) + P(X=2)

Using the same formula:

$P(X=0)=\dfrac{14!}{0!\cdot 14!}\times 0.12^0\cdot 0.88^{14}$

$P(X=0)=0.1670$

$P(X=1)=\dfrac{14!}{1!\cdot 13!}\cdot 0.12^1\cdot 0.88^{13}$

$P(X=1)=0.3188$

$P(X=2)=\dfrac{14!}{2!\cdot 12!}\codt0.12^2\cdot 0.88^{12}$

$P(X=2)=0.2826$

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.7685

(c) Find the probability that more than two of them fail the test.

The probability that more than two of them fail the test is equal to 1 less the probability that exactly 0, or exactly 1, or exactly 2 fail the test:

P( X > 2) = 1 - P( X = 0) - P(X = 1) - P(X = 2)

P X > 2) = 1 - [P(X=0) + P(X = 1) + P(X = 2)]

P (X > 2) = 1 - [0.7685]

P (X > 2) = 0.2315

(d) Would it be unusual for none of them to fail the test?

Remember that not failing the test is the fail of the binomial distribution. Thus, none of them failing the test is the same as all of them passing the test.

You can find the probability that all the automibles pass the emission tests by multiplying the probability of passing the test (0.88) 14 times.

Then, the probability that none of them to fail the test is equal to:

$(1-p)^{14}\\\\(0.88)^{14}=0.1671$

That means that the probability than none of the automobiles of the sample fail the test is 16.71%.

Unusual events are usually taken as events with a probability less than 5%. Thus, this event should not be considered as unusual.

5 0

3 years ago

PLEASE HELP ASAPP!!!!! NO JOKES ONLY SERIOUS ANSWERS

bogdanovich [222]

E1,1 F5,3 G5,7 H1,6 bc when rotating 90 a,b becomes -b,a

8 0

3 years ago