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Strike441 [17]
3 years ago
12

Tell me how to decompose 792

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

break it down to prime factorization

so the ans will be 2^3 * 3^2 *11

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-12 divided by 3 x (-8 +(-4)^2 - 6) + 2
son4ous [18]

Answer:

this is the correct graph

8 0
3 years ago
HELP PLEASE!!!!!BRAINLIEST
Greeley [361]
That is false because you have to subtract the exponents not divide
4 0
3 years ago
Read 2 more answers
Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b
4vir4ik [10]
The value of "b" is the y-intercept.

In order to figure out slope-intercept form you need 1 coordinate and the slope.
1) Find the slope, using the 2-point slope formula: "m= y2-y1 / x2-x1".
   ex. m= -5 - 3 / -4 - -6   (simplify)--->   m= -4

2) Fill in the blanks for point-slope formula: "y - y1 = m (x - x1)"
(choose one coordinate, it doesn't matter which one)
   ex. y - -5 = -4 (x - -4)

3) Then use basic algebra to simplify.


7 0
3 years ago
Two shops, Lidal and Oldi, sell the same brand of toilet rolls but with different package sizes.
Ugo [173]

Answer:

Oldi is best value

Step-by-step explanation:

<u>Lidal</u>

8 rolls for £3.76

72 rolls for £3.76*9= £33.84

<u>Oldi</u>

9 rolls for £4.14

72 rolls for £4.14*8= £33.12

Oldi offers better price for 72 rolls

5 0
3 years ago
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
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