Yes, because I think two could work
The line contains point (2, 0) and (-5, 4).
y - 0 = (4 - 0)/(-5 - 2) (x - 2)
y = -4/7 (x - 2)
7y = -4(x - 2)
7y = -4x + 8
4x + 7y = 8
Hello from MrBillDoesMath!
Answer:
x = 0, 7
Discussion:
f(g(x)) =
f ( x^2-7x) =
1/ ( x^2 - 7x)
The points NOT in the domain are those where the denominator, x^2 - 7x = 0.
x^2 - 7x = 0 => factor x from each term
x(x-7) = 0 => one or both terms must each 0
x = 0 or x =7
Thank you,
MrB
Start at the point (2, -3) and then go up 3 and to the right 4 a few points and then go down 3 and to the left 4 a few points and then from there you can get an equation out of it
