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bazaltina [42]
3 years ago
8

Please help me you'll get brainliest

Mathematics
2 answers:
horrorfan [7]3 years ago
6 0

Answer:

3

Step-by-step explanation:

So the diagram shows the weight of each puppy in pounds.

Each dot is a puppy.

The first dot is at 1/4 pounds meaning you have one dog that weights that much.

At the other end, you have 3 dots at 3/4 pounds meaning you have one dog that weights that much.

The heaviest puppy is 3/4 and the lightest is 1/4.

So dividing 3/4 / 1/4 = 3/4 * 4 = 3.

So 3 times as great

neonofarm [45]3 years ago
6 0

Answer:

3

Step-by-step explanation:

1/4 x 3 = 3/4

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Simplify y 2 + 11y - 6y + y 2. y4 + 5 y4 + 5y 2y 2 + 5 2y 2 + 5y
Dmitrij [34]

Answer:

2y^2 +5y

Step-by-step explanation:

y^2 + 11y - 6y + y^2

Combine like terms

2y^2 +5y

3 0
3 years ago
Read 2 more answers
Find the missing value ​
lapo4ka [179]

Answer:

-10

Step-by-step explanation:

since the answer is positive, we need a negative number, if we use -10,two negatives makes a positive, so it becomes

-8 +10=2

4 0
4 years ago
Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
A line segment has endpoints (-2,-3) and (4,4). Find the length of the segment and find the midpoint.
uysha [10]
\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -2 &,& -3~) 
%  (c,d)
&&(~ 4 &,& 4~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[4-(-2)]^2+[4-(-3)]^2}\implies d=\sqrt{(4+2)^2+(4+3)^2}
\\\\\\
d=\sqrt{36+49}\implies \boxed{d=\sqrt{85}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -2 &,& -3~) 
%  (c,d)
&&(~ 4 &,& 4~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{4-2}{2}~~,~~\cfrac{4-3}{2} \right)\implies \left(\cfrac{2}{2}~~,~~\cfrac{1}{2}  \right)\implies \boxed{\left(1~,~\frac{1}{2}  \right)}
5 0
4 years ago
Choose the sets of equivalent expressions (select all that apply)
Alex17521 [72]

9514 1404 393

Answer:

  B, E, F

Step-by-step explanation:

A. 4x and 5 + x

B. 2b + b and 3b

C. 3x and 3 + x

D. a ÷ 1/3 and 1/3 a

E. a ÷ 1/3 and a × 3

F. 1a and a

_____

<em>Comment on the above</em>

ax is multiplication of x by 'a'. a+x is addition. They are different operations.

x/(1/3) is not the same as x(1/3). Multiplication and division are different operations.

7 0
3 years ago
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