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aleksandr82 [10.1K]
2 years ago
6

PLEASE HELP ME BY TODAY ((UNIT RATE)) I WILL GIVE BRAINLIEST, WORTH 20 POINTS

Mathematics
2 answers:
Leona [35]2 years ago
7 0

Answer: Steve can train 80 dogs.

Step-by-step explanation:

How many dogs he can train divided by how many hours is: 48/6 = 8.
He is able to train 8 dogs per hour. So: 8 x 10 = 80.

SpyIntel [72]2 years ago
4 0

Answer:

80

Step-by-step explanation:

48 ÷ 6 = 8 per hour

8 x 10 hours = 80 dogs

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What is the volume of the cone? A. 4258.44 yd3 B. 2876.7 yd3 C. 4625.36 yd3 D. 2787.64 yd3
zepelin [54]
The answer is 2787.64, D
5 0
3 years ago
Read 2 more answers
Xiao Ming is now 15 years
insens350 [35]

Answer:

16

Step-by-step explanation:

father's age=46

half of father's age=46/2=23

Xiao's age=15

so when Xiao is half of her father age =23-15=8

then add 8 to his sister's age

so 8+8=16

hope its was helpful<3<3

plz rate the answer

4 0
4 years ago
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Look at the table representing the distance covered by a car accelerating from 0 miles per hour. The table shows a relationship.
vfiekz [6]

quadratic

second

16

8

✌️

8 0
3 years ago
I will mark u as brainliest if u answer this!!
lawyer [7]

i)On z, define a∗b=a−b
here aϵz
+
and bϵz
+

i.e.,a and b are positive integers
Let a=2,b=5⇒2∗5=2−5=−3
But −3 is not a positive integer
i.e., −3∈
/
z
+

hence,∗ is not a binary operation.
ii)On Q,define a∗b=ab−1
Check commutative
∗ is commutative if,a∗b=b∗a
a∗b=ab+1;a∗b=ab+1=ab+1
Since a∗b=b∗aforalla,bϵQ
∗ is commutative.
Check associative
∗ is associative if (a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(ab+1)∗c=(ab+1)c+1=abc+c+1
a∗(b∗c)=a∗(bc+1)=a(bc+1)+1=abc+a+1
Since (a∗b)∗c

=a∗(b∗c)
∗ is not an associative binary operation.
iii)On Q,define a∗b=
2
ab
​

Check commutative
∗ is commutative is a∗b=b∗a
a∗b=
2
ab
​

b∗a=
2
ba
​
=
2
ab
​

a∗b=b∗a∀a,bϵQ
∗ is commutativve.
Check associative
∗ is associative if (a∗b)∗c=a∗(b∗c)
(a∗b)∗c=
2
(
2
ab
​
)∗c
​
=
4
abc
​

(a∗b)∗c=a∗(b∗c)=
2
a×
2
bc
​

​
=
4
abc
​

Since (a∗b)∗c=a∗(b∗c)∀a,b,cϵQ
∗ is an associative binary operation.
iv)On z
+
, define if a∗b=b∗a
a∗b=2
ab

b∗a=2
ba
=2
ab

Since a∗b=b∗a∀a,b,cϵz
+

∗ is commutative.
Check associative.
∗ is associative if $$
(a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(2
ab
)
∗
c=2
2
ab

c
a∗(b∗c)=a∗(2
ab
)=2
a2
bc


Since (a∗b)∗c

=a∗(b∗c)
∗ is not an associative binary operation.
v)On z
+
define a∗b=a
b

a∗b=a
b
,b∗a=b
a

⇒a∗b

=b∗a
∗ is not commutative.
Check associative
∗ is associative if $$
(a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(a
b
)
∗
c=(a
b
)
c

a∗(b∗c)=a∗(2
bc
)=2
a2
bc


eg:−Leta=2,b=3 and c=4
(a∗b)
∗
c=(2∗3)
∗
4=(2
3
)
∗
4=8∗4=8
4

a∗(b∗c)=2
∗
(3∗4)=2
∗
(3
4
)=2∗81=2
81

Since (a∗b)∗c

=a∗(b∗c)
∗ is not an associative binary operation.
vi)On R−{−1}, define a∗b=
b+1
a
​

Check commutative
∗ is commutative if a∗b=b∗a
a∗b=
b+1
a
​

b∗a=
a+1
b
​

Since a∗b

=b∗a
∗ is not commutatie.
Check associative
∗ is associative if (a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(
b+1
a
​
)
∗
c=
c
b
a
​
+1
​
=
c(b+1)
a
​

a∗(b∗c)=a∗(
c+1
b
​
)=
c+1
b
a
​

​
=
b
a(c+1)
​

Since (a∗b)∗c

=a∗(b∗c)
∗ is not a associative binary operation
6 0
3 years ago
Is the following statement a good definition? Why? An integer is divisible by 100 if and only if its last two digits are zeros.
nikitadnepr [17]

The given statement is An integer is divisible by 100 if and only if its last two digits are zeros.

The two conditional statements that can be made are:

1) If an integer is divisible by 100 its last two digits are zeros.

This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have the last two digits zeros.

<h3>What happen when last two digit of the number are 0?</h3>

2) If the last two digits of an integer are zeros, it is divisible by 100.

This is also true. If the last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.

Therefore, the two conditional statements that are formed are both true.

So, option A is the correct answer.

Yes, it is. When the definition is separated into two conditional statements, both of the statements are true.

To learn more about the integer visit:

brainly.com/question/17695139

#SPJ1

4 0
2 years ago
Read 2 more answers
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