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yanalaym [24]
2 years ago
10

Is the following statement a good definition? Why? An integer is divisible by 100 if and only if its last two digits are zeros.

No, it is not. When the definition is separated into two conditional statements, one of the statements is false. Yes, it is. When the definition is separated into two conditional statements, one of the statements is true. Yes, it is. When the definition is separated into two conditional statements, both of the statements are true. No, it is not. When the definition is separated into two conditional statements, both of the statements are false.
Mathematics
2 answers:
Snowcat [4.5K]2 years ago
5 0

The given statement is An integer is divisible by 100 if and only if its last two digits are zeros.

<h3>What is Integers?</h3>

An integer is a number with no decimal or fractional part, from the set of negative and positive numbers, including zero.

The two conditional statements that can be made are:

1) If an integer is divisible by 100 its last two digits are zeros.

This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have the last two digits zeros.

2) If the last two digits of an integer are zeros, it is divisible by 100.

This is also true. If the last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.

Therefore, the two conditional statements that are formed are both true.

So, option A is the correct answer.

Yes, it is. When the definition is separated into two conditional statements, both of the statements are true.

Learn more about integer from:

brainly.com/question/17695139

#SPJ1

nikitadnepr [17]2 years ago
4 0

The given statement is An integer is divisible by 100 if and only if its last two digits are zeros.

The two conditional statements that can be made are:

1) If an integer is divisible by 100 its last two digits are zeros.

This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have the last two digits zeros.

<h3>What happen when last two digit of the number are 0?</h3>

2) If the last two digits of an integer are zeros, it is divisible by 100.

This is also true. If the last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.

Therefore, the two conditional statements that are formed are both true.

So, option A is the correct answer.

Yes, it is. When the definition is separated into two conditional statements, both of the statements are true.

To learn more about the integer visit:

brainly.com/question/17695139

#SPJ1

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The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to
jarptica [38.1K]

Answer:

  • The width = x = 14
  • The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let  l  = length,  w = width,  A = area =  l×w , and  P  = perimeter =  2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to  2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

x^2-11x=42

\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}

x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2

x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}

\left(x-\frac{11}{2}\right)^2=\frac{289}{4}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solving

x-\frac{11}{2}=\sqrt{\frac{289}{4}}

x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}

x-\frac{11}{2}=\frac{\sqrt{289}}{2}

x-\frac{11}{2}=\frac{17}{2}

x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}

x=14

similarly solving

x-\frac{11}{2}=-\sqrt{\frac{289}{4}}

x-\frac{11}{2}=-\frac{17}{2}

x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}

x=-3

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

  • The width = x = 14
  • The length = x+5 = 14+5 = 19

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Which point is a solution to the equation 2x - y = 4?
Natasha_Volkova [10]

Answer:

2<em>x=  1 /2 y+ 2</em>

Step-by-step explanation:

Solve for x.

<em>2x−y=4</em>

Add y to both sides.

<em>2x−y+y=4+y </em>

<em>2x=y+4</em>

Divide both sides by 2.

<em>2x /2  =  y+4 /2</em>

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It’s easy just re group
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In a parallelogram, opposite sides have the same length. 
3x + 9 = 5x -5
group like terms on one side
9 + 5 = 5x -3x
14 = 2x
x is 7.
Since AB is 5x -5 
AB = 5(7) -5
AB = 30.

BX is half of the line DB. So BX = DX
5y = 7y - 10
10 = 7y -5y
10 = 2y
y =5.
Since BX = 7y - 10
BX = 7(5) -10
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3 years ago
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