Given that
3 cos 80° cosec 10° + 2 sin 59° sec 31°
⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°
We know that
sin (90° - A) = cos A
cos (90°-A) = sin A
⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°
⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)
⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)
⇛3 (1) + 2(1)
⇛3+2
⇛5
<u>Answer</u><u>:</u> Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> (sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
brainly.com/question/87846?referrer
Answer:
OPTION B ,CF
Step-by-step explanation:
AS THERE ARE 4 DIAGONALS=CF,BG,AH,DE
BUT IN OPTION CF NO OTHER DIAGONAL IS GIVEN..
Answer:
see explanation
Step-by-step explanation:
(a)
Given f(x) then f(x) + c represents a vertical translation of f(x)
• If c > 0 then a shift up of c units
• If c < 0 then a shift down of c units
f(x) + 5 represents a shift up of 5 units, thus
(2, - 3 ) → (2, - 3 + 5 ) → (2, 2 )
(b)
Given f(x) then - f(x) represents a reflection of f(x) in the x- axis
Under a reflection in the x- axis
a point (x, y ) → (x, - y ), thus
(2, - 3 ) → (2, 3 )
Answer:
y=-1/2x-2
Step-by-step explanation:
simplify the expression to get the equation in slope intercept form, and find the graph that fits it