Answer:
<h2><em>
Three to the three fifths power.</em></h2>
Step-by-step explanation:
The given expression is
![\sqrt{3\sqrt[5]{3} }](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%20%7D)
To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:
![\sqrt[n]{x^{m}}=x^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
Applying the property, we have:
![\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D%5Csqrt%7B3%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%283%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
Now, we multiply exponents:
Then, we sum exponents to get the simplest form:
![3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }](https://tex.z-dn.net/?f=3%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B10%7D%7D%3D3%5E%7B%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B10%7D%7D%20%3D3%5E%7B%5Cfrac%7B10%2B2%7D%7B20%7D%7D%3D3%5E%7B%5Cfrac%7B12%7D%7B20%7D%7D%20%20%5C%5C%5Ctherefore%20%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D)
Therefore, the right answer is <em>three to the three fifths power.</em>
Answer:
Halogen
Step-by-step explanation:
Halogen is a little more efficent but not as efficient as LED lighting.
When we are looking for the mid point, we are looking for a point that is an equal distance from point R and S.
Since the x value has no change, we can ignore it.
For the y value, we want to simply find the difference between the points (7 - 1 = 6) and then divide that value by 2 (6 / 2 = 3).
You can then subtract that value from the higher Y value, where you will get 4.
Leaving you with the coordinate (3,4)
Hope this helped. There are definitely more ways you could find to solve this, but this works best for this problem.
Answer:
ummm whats the salary ._.
Step-by-step explanation:
Answer:
∠A = 6x + 4
Step-by-step explanation:
Hello There!
We are given the exterior angle ∠ACD and an interior angle ∠B
If you didn't know this is the rule for exterior angles of a triangle:
An exterior angle is equal to the sum of its opposite interior angles
so ∠ACD = ∠A + ∠B ( ∠A and ∠B being the opposite interior angles)
So with the information that we are given we plug them into their corresponding angle
then we would have
8x+5 = ∠A + 2x + 1
now we solve for A
Well how do we solve for A?
Well we have to isolate the variable
To do so we want to get rid of 2x + 1
We do that by subtract each side by 2x and 1
8x + 5 - (2x + 1 ) = 6x + 4
we're left with
∠A = 6x + 4
