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Hunter-Best [27]
2 years ago
7

A manager is comparing wait times for customers in a coffee shop based on which employee is

Mathematics
1 answer:
anyanavicka [17]2 years ago
8 0

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

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O.9c + 1.89r = 17.01 c=18.9 - 2.1r equation answer
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Answer:

c=18.90-2.1r

Step-by-step explanation:

<u><em>The complete question is</em></u>

A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per  pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this  situation.

Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.

Then, explain when it might be helpful to write the equation in these forms.

a. c=18.9-2.1r. b. r= -10÷2c+9​

we have that

The linear equation in standard form is

0.90c+1.89r=17.01

where

c is the pounds of chicken

r is the pounds of ribs

step 1

Solve the equation for c

That means ----> isolate the variable c

Subtract 1.89r both sides

0.90c=17.01-1.89r

Divide by 0.90 both sides

c=(17.01-1.89r)/0.90

Simplify

c=18.90-2.1r

step 2

Solve the equation for r

That means ----> isolate the variable r

Subtract 0.90c both sides

1.89r=17.01-0.90c

Divide by 1.89 both sides

r=(17.01-0.90c)/1.89

Simplify

r=9-0.48c

therefore

The equation c=18.90-2.1r is equivalent

The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.

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