This can be calculated using the formula:
P = L((r/n)*(1 + r/n)^(n*t))/((1 + r/n)^(n*t) - 1)
Where:
L = 4759
r = 0.209
n = 12
t = 3
So plugging in our data:P = 4759((0.209/12)*(1 + 0.209/12)^(12*3))/((1 + 0.209/12)^(12*3) - 1)
Which will give us the amount of: $179.05 is the monthly repayments.
Other info:
Total interest:$1,686.80
Total cost:$6,445.80
Answer:
sqrt166, 13, 14
Step-by-step explanation:
Answer:
b $3,272.43
Step-by-step explanation:
A = p(1+r/n)^nt
Where
A= future value
P= principal = $2500
r= interest rate = 6.75% = 0.0675
n = number of periods = 12
t = time = 4 years
A = p(1+r/n)^nt
= 2500(1+0.0675/12)^12*4
= 2500(1+0.005625)^48
= 2500(1.005625)^48
= 2500(1.3089737859257)
= 3272.4344648144
Approximately
A= $3272.43
He will have $3272.43 to give as down payment in 4 years
Answer:
log(4)
Step-by-step explanation:
log(2) + log(2)
log(2×2)
log(4)
A think it is all of the above because each rope is the same amount
