In the given question , we have a function given , which is

And we need to find the value of y when x=5.
So we substitute 5 for x and solve for y, that is

And on rounding to the nearest tenths, we will get

So when x=5, y=0.4
Answer:
-1 1/24
Step-by-step explanation:
Answer:
A. 1/2
Step-by-step explanation:
3/16 / 3/8
3/3 = 1
16/8 = 2
1/2
⇒I will first isolate y together with its coefficient k by placing
to the right hand side...

⇒Now to leave y independent we have to divide ky by the coefficient of y which in this case is k.
⇒Meaning k will divide all the terms in the equation.

⇒Attached is the answer.