From the information given:
Random wins 2000 800 400 0
Probabilities 1/10^4 4/10^4 10/10^4 9985/10^4
thus the expectation will be:
E(x)=[2000+4*800+4000+9985*0]/10^4
E(x)=9200/10000
E(x)=$0.92
Steps:
Simplify:
5³/5⁷
= 5³/5⁷
= 5*5*5/ 5*5*5*5*5*5*5
=1/5⁴
=1/625 (Decimal: 0.0016)
Steps by Step:
5³/5⁷
=125/5⁷
=125/78125
=1/625
Answer: =1/625 (Decimal: 0.0016)
Please mark brainliest
<em><u>Hope this helps.</u></em>
Wait what? Erm.. could you give is a little more detail so I can figure this out??
Answer:
x = 45 when y = 20 and z = 6
Step-by-step explanation:
The general formula here is y = kx/z²
If x = 24 and y = 6, z = 8, so:
y = kx/z² becomes 6 = k(24)/8², and:
6 1
k = ---------------- = -------------- = 16
24/64 4/64
Then y = 16x/z², and so, if y = 20 and z = 6 (check this!), then:
20 = 16x/36, or 16x = 720, or x = 45
x = 45 when y = 20 and z = 6
