All categories

2 years ago

Please answer, thank you. Image below.

Mathematics

1 answer:

vovikov84 [41]2 years ago

5 0

Answer:

Top Image: 56°

Bottom Image: 134°

Step-by-step explanation:

I'm not sure which image you have a question on, so I'll just solve both.

Top Image:

We know that the sum of the angles will add up to 180 and that the angles of the triangle are f, f, and 68°. Therefore, we can set up the following equation:

f + f + 68° = 180°

Solving this gets f = 56°

Bottom Image:

We know that the sum of the angles will add up to 180 and that the angles of the triangle are 23°, 23°, and g. Therefore, we can set up the following equation:

23° + 23° + g = 180°

Solving this gets g = 134°

You might be interested in

Is the formula s=(n-2)180

Phantasy [73]

Answer:

Number of sides of the polygon

Step-by-step explanation:

The formula $S=(n-2)180$ is the sum of the measures of interior angles. So that's what S stands for. The only other variable remaining is n which is the number of sides of the polygon.

There's nothing I can do to help you understand this, you just have to memorize it.

5 0

3 years ago

Yolanda made $192 for 12 hours of work. At the same rate, how many hours would she have to work to make $272?

denpristay [2]

Answer:

17 hours

take $192 and divide it by 12 so you know how much they make per hour

$192 / 12 = 16

then you're going to take $272 and divide it by what you know now - how much they make per hour (this will get you how many hours they worked)

$272 / 16 = 17

6 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

A scientist has a sample of the radioactive isotope bismuth-212. The isotope decays exponentially as shown in the table. Time (s

luda_lava [24]

Answer:

f(x) = 30 • 0.989x

Step-by-step explanation:

Given the data :

10 26.8

20 23.9

30 21.3

40 19

50 16.9

60 15.1

Using technology, the exponential model equation obtained by plotting the data is :

y = 30.068(0.989)^x

Based on the general exponential formula :

y = ab^x

y = predicted value

Initial value, a = 30.068

Rate = b = 0.989

The most appropriate model equation from the options given is :

f(x) = 30 • 0.989^x

7 0

3 years ago

In a bag of blue and yellow marbles, the ratio of blue marbles to yellow marbles is 3:5. if the bag contains 60 yellow marbles,

fiasKO [112]

Double the numbers by themselves for 5 times and you get the ration of blue to yellow balls of 96:60

4 0

4 years ago