Answer:
(2,4)
Step-by-step explanation:
Answer:
I don't know but I need points, look it up on go0gle
1. Drawn a straight line AB =7 cm with the help of ruler.
2. With the help of compass drawn an arc from A and at the point where it cuts AB from that point made another arc drawn an arc cutting the previous arc.
3. From A drawn a straight line joining the arc and extend it to M.
4. With the help of ruler measured 5 cm and mark it as AC.
5. Joined BC and we get the required triangle.
6. From C drawn an arc and make it cut on AC and BC and from the point it cuts AC and BC drawn arc cutting each other and extend a line from point C extend a line to the point point of intersection of two arc.
7. Similarly we do for A and the point where the two line intersect denoted as O.
8. Made a perpendicular from O on AB this perpendicular will be radius and taking O as centre we draw a circle this is our incircle.
9. And AN is our locus of points equidistant from two lines AB and AC.
We need to construct a circle inscribed in triangle that is incircle it can be done by making angle bisector of two sides the point where it intersect will be incentre. The centre of required circle.
The angle bisector is the locus where points are equidistant from two sides.
<h2 />
Please review the sum and difference formulas for the trig functions.
In this case you have the difference between two angles u and v and want to find the cosine of this difference.
Here's the appropriate formula:
cos (a-b) = cos a cos b + sin a sin b
Given that sin u = -9/41, equal to the opp side over the hyp., we must find the length of the adj. side and then u itself.
opp side = - 9
hyp = 4
adj side = sqrt( 18+4) = sqrt(22)
Find the side opp angle v in a similar manner.
Then cos (u-v) = cos u cos v + sin u sin v becomes
= (cos u)(15/17) + (-9/41)(sin v) (where you must find cos u and sin v)
See what you can do, then return and comment here if you need further help. Good luck.