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Mamont248 [21]
3 years ago
12

50 hundred thousands equals how many tenths?

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
It would be 100 tens your welcome.
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Help please I need it please please help me in it
Snezhnost [94]

Answer:

115.08

Step-by-step explanation:

6 0
3 years ago
What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
3 years ago
A square on a coordinate plane has the points A(0, 0), B(0, 5), C(5, 5) and D(5, 0). If Square ABCD is rotated about the origin
Georgia [21]

Answer:

B. 5 units

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, dilation, rotation or translation.

If a point X(x,y) is rotated about the origin 180 degrees clockwise the new point is at X'(-x, -y).

If the square with vertices at A(0, 0), B(0, 5), C(5, 5) and D(5, 0) is rotated about the origin 180 degrees clockwise the new points are at A'(0, 0), B'(0, -5), C'(-5, -5), D'(-5, 0)

A square has four equal sides. The distance between two points X(x_1,y_1)\ and\ Y(x_2,y_2) is:

|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Hence:

|A'B'|=\sqrt{(0-0)^2+(-5-0)^2} =5

3 0
3 years ago
Help Number three please!!!
Lubov Fominskaja [6]

Step-by-step explanation:

108-ambulance

100- police

1098-child laber

5 0
3 years ago
What is the value of the six in 106,534
aleksley [76]
6,000 because its in the thousandth and so since its a six in the thousandths its 6,000 remember the comma
8 0
3 years ago
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