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Tcecarenko [31]
3 years ago
13

What is not a part of the digestive system

Chemistry
1 answer:
Alja [10]3 years ago
7 0

Answer:

Trachea is not the part of digestive system

Explanation:

Trachea is the part of the respiratory system

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What is the coefficient of Oxygen in the balanced reaction below:
Oksana_A [137]

The coefficient of Oxygen in the balanced reaction : 3

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

C2H4+ O2--> CO2+H2O​

Required

The coefficient of Oxygen

Solution

  • Give a coefficient

C₂H₄+ aO₂⇒ bCO₂+cH₂O​

C, left=2, right=b⇒b=2

H, left=4, right=2c⇒2c=4⇒c=2

O, left=2a, right=2b+c⇒2a=2b+c⇒2a=2.2+2⇒2a=6⇒a=3

The equation becomes :

<em>C₂H₄+ 3O₂⇒ 2CO₂+2H₂O​</em>

4 0
3 years ago
How does modern periodic table explain the cause of periodicity. ​
pickupchik [31]

Answer:

The cause of periodicity in properties is the repetition of similar outer electronic configuration after certain regular intervals. For example, all the elements of group 1 i.e. alkali metals have a similar outer electronic configuration, ns1.

5 0
3 years ago
How many liters of the antifreeze ethylene glycol [CH2(OH)CH2(OH)] would you add to a car radiator containing 6.50 L of water if
sergeinik [125]
 <span>16 = m x 1.86 
m = 8.60 = moles solute / 6.50 Kg 

moles solute = 55.9 

mass solute = 55.9 x 62.068 g/mol=3470 g 

V = 3479/ 1.11 =3126 mL= 3.13 L 

delta T = 8.60 x 0.512 =4.40 
boling point = 104.4 °C

Hope this helps.</span>
4 0
3 years ago
Read 2 more answers
Compare the conditions required for snow and rain to form.
andrew11 [14]

Answer:

rain sleet ir snow si it has to be harsh

4 0
3 years ago
How many grams of CO2 are produced by the combustion of 289 g of a mixture that is 28.6% CH4 and 71.4% C3H8 by mass?
serg [7]

845 grams of CO2 are produced by the combustion of 289 g of a mixture that is 28.6% CH4 and 71.4% C3H8 by mass.

Explanation:

The mixture of methane and propane is butane with molecular formula

C4H12

on combustion the balanced reaction is:

C4H12 + 7 O2 ⇒   4CO2  + 6  H20

Molar mass of butane = 60.13 grams/mole, mass of C4H12 = 289 grams

number of moles of C2H12 is calculated by using the formula:

n = \frac{mass}{molar mass of 1 mole}

putting the values to know the moles of C4H12:

n = \frac{289}{60.13}

n = 4.8 moles of C4H12

from the balanced equation:

1 mole of C4H12 undergoes combustion to form 4 moles of CO2

thus, 4.8 moles when undergoes combustion will form x moles of CO2

\frac{4}{1}= \frac{x}{4.8}

X = 4 X 4.8

x = 19.2 moles of CO2 is formed.

to convert mole into mass, formula used:

mass = number of moles x atomic mass

         = 19.2 x 44.01

          = 844.99 grams of CO2 is formed.

3 0
4 years ago
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