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gregori [183]
3 years ago
9

2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specifi

c heat of the solution is 4.18 J/g·⁰C. Calculate the amount of heat associated with the water.
Chemistry
1 answer:
RUDIKE [14]3 years ago
5 0
<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>
  • The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

Therefore;

Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

Thus, Heat gained by the substance = heat lost by water

Heat associated with the water  

Mass of water = 75 g

Change in temperature = 4.4°C

Specific heat capacity =  4.18 J/g·⁰C

Heat = mcΔT

        = 75 g × 4.18 J/g·⁰C × 4.4 °C

        =1379.4 Joules

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