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gregori [183]
2 years ago
9

2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specifi

c heat of the solution is 4.18 J/g·⁰C. Calculate the amount of heat associated with the water.
Chemistry
1 answer:
RUDIKE [14]2 years ago
5 0
<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>
  • The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

Therefore;

Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

Thus, Heat gained by the substance = heat lost by water

Heat associated with the water  

Mass of water = 75 g

Change in temperature = 4.4°C

Specific heat capacity =  4.18 J/g·⁰C

Heat = mcΔT

        = 75 g × 4.18 J/g·⁰C × 4.4 °C

        =1379.4 Joules

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See explanation.

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Hello there!

In this case, considering the given information, it is not possible to figure out such order of reaction with respect to water as it is not involved in the given chemical reaction:

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3 years ago
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Montano1993 [528]

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