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Thepotemich [5.8K]
2 years ago
14

Help, please

Physics
1 answer:
kvv77 [185]2 years ago
5 0

Answer:

<em>I </em><em>am</em><em> </em><em>going</em><em> to</em><em> </em><em>answer</em><em> </em><em>the</em><em> </em><em>questions</em><em>,</em><em> according</em><em> to</em><em> the</em><em> </em><em>num</em><em>bers</em><em> </em><em>of</em><em> </em><em>empty</em><em> </em><em>spaces </em><em>to</em><em> </em><em>fill</em><em>,</em><em>1</em><em>.</em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em> </em><em>charge</em><em>,</em><em>2</em><em>.</em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em><em>3</em><em>.</em><em>f</em><em>i</em><em>e</em><em>l</em><em>d</em><em> </em><em>lines</em><em>,</em><em>4</em><em>.</em><em>n</em><em>e</em><em>g</em><em>a</em><em>t</em><em>i</em><em>v</em><em>e</em><em>s</em><em>,</em><em>5</em><em>.</em><em>p</em><em>o</em><em>s</em><em>i</em><em>t</em><em>i</em><em>v</em><em>e</em><em>,</em><em>6</em><em>.</em><em>a</em><em>f</em><em>f</em><em>e</em><em>c</em><em>t</em><em>e</em><em>d</em><em>,</em><em>7</em><em>.</em><em>a</em><em>t</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>,</em><em>8</em><em>.</em><em>r</em><em>e</em><em>p</em><em>e</em><em>l</em><em>.</em>

Explanation:

if u read it filling in the spaces using this answers,u will understand

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Help for 50 points thank you
Korolek [52]

Answer:

Explanation:

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. ... Therefore, the oscillating material does not move far from its initial equilibrium position. Mechanical waves transport energy. This energy propagates in the same direction as the wave.

4 0
3 years ago
Read 2 more answers
A particle of mass m= 2.5 kg has velocity of v = 2 i m/s, when it is at the origin (0,0). Determine the z- component of the angu
melomori [17]

Answer:

please read the answer below

Explanation:

The angular momentum is given by

|\vec{L}|=|\vec{r}\ X \ \vec{p}|=m(rvsin\theta)

By taking into account the angles between the vectors r and v in each case we obtain:

a)

v=(2,0)

r=(0,1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

b)

r=(0,-1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

c)

r=(1,0)

angle = 0°

r and v are parallel

L = 0kgm/s

d)

r=(-1,0)

angle = 180°

r and v are parallel

L = 0kgm/s

e)

r=(1,1)

angle = 45°

L = (2.5kg)(2\frac{m}{s})(\sqrt{2})sin45\°=5kg\frac{m}{s}

f)

r=(-1,1)

angle = 45°

the same as e):

L = 5kgm/s

g)

r=(-1,-1)

angle = 135°

L=(2.5kg)(2\frac{m}{s})(\sqrt{2})sin135\°=5kg\frac{m}{s}

h)

r=(1,-1)

angle = 135°

the same as g):

L = 5kgm/s

hope this helps!!

4 0
3 years ago
This particle is found in the nucleus and adds mass to the nucleus, but changing its number does not change what the element is.
Sliva [168]
Adding neutron to the nucleus creates new isotopes of that element. Mass of the nucleus will increase if you add neutron to it but element will remain the same. If you add proton to the nucleus, mass of the nucleus will change but also element will also change. That is, atom of the element will change. 

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3 years ago
What features form where two continental plate come together
ExtremeBDS [4]
Ridges, mountains, and volcanoes!

3 0
3 years ago
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An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

u -v= d

u=71+26=97\ cm

We need to calculate the focal length

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

\dfrac{1}{f}=-\dfrac{71}{2522}

f=-35.52\ cm

The focal length of the lens is 35.52.

(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value in to the formula

\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}

\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}

\dfrac{1}{v}=-\dfrac{124}{2755}

v=-22.21\ cm

We need to calculate the magnification

Using formula of magnification

m=\dfrac{v}{u}

m=\dfrac{22.21}{95}

m=0.233

The magnification is 0.233.

The image is virtual.

Hence, This is the required solution.

4 0
3 years ago
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