<span>1. Radio-Lights at night -
2. Microwave to heat up your food 3. (and it makes your computer and wifi work that allows you to login and get us to do your homework for you).</span>
Answer:
Explanation:
As we know that the dimensions of the base of the tank is given as
now the base area is given as
now we know that volume of the liquid filled in the tank is given as
now we will differentiate it with respect to time both sides
here we know that
now we have
Answer:
W= - 1414.48 J : Work done by the friction force on the box.
Explanation:
Work concept
The work (W) of a given force is defined as the product of the force (F) by the distance(d) in which the force acted.
W= F*d :in (Joules) Formula (1)
Friction force concept
Ff=μk*N Formula (2)
μk=coefficient of kinetic friction
N= Normal force
We apply Newton's first law for forces in the direction of the axis y
∑Fy=0 Equation (1)
The forces acting on the box in the direction of the axis and are the following:
- Fy=Force of 210 N in y= 210*sen 39°= 132.16 N ( +y)
- W=Weight of box= m*g=30kg*9.8m/s² = 294N (-y)
- N =Normal force ( +y)
We apply equation (1) and do the algebraic sum of forces in y
Fy+N-W=0
132.16+N-294=0
N= 294-132.16=161.84 N
We apply formula (2) to calculate Ff:
Ff= -0.23*161.84=-37,22N The frictional force is negative because it goes in the opposite direction to the displacement.
We apply formula (1) to calculate the work done by the friction force on the box
W= - 37,22 N * 38 m = -1414.48 N*m = -1414.48 J