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3 years ago

What is the speed of sound in air when the temperature is 20°C?

Physics

2 answers:

Anarel [89]3 years ago

5 0

The answer to your question is 343 m/s

Minchanka [31]3 years ago

4 0

Answer:

The speed of sound in air when the temperature is 20°C is 343 m/s.

Explanation:

Given that,

Temperature T = 20°C = 20+273=293 K

The speed of sound in air is the distance traveled divided by time.

We know that,

The relation between the speed of sound in air and temperature is defined as:

$v= 331\sqrt{\dfrac{T}{273}}$

Where, T = temperature in Kelvin

v = speed of sound in air

We substitute the value into the formula

$v = 331\sqrt{\dfrac{293}{273}}$

$v = 342.9 = 343\ m/s$

The speed of sound in air is 331 m/s at 0° C, 343 m/s at 20°C and 346 m/s at 25°C.

Hence, the speed of sound in air when the temperature is 20°C is 343 m/s.

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A hand pushes two blocks, A and B, along a frictionless table for a distance d. When the hand starts to push, the blocks are mov

Kitty [74]

<span>net work = change in kinetic energy

for Block B, we just have the force from block A acting on it
F(ab)d= .5(1)vf² - .5(1)(2²)
F(ab)d= .5vf² - 2

Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction

10-F(ba)d = .5(4)vf² - .5(4)(2²)
10-F(ba)d = 2vf² - 8
F(ba)d = 18 - 2vf²

now we have two equations:
F(ba)d = 18 - 2vf²
F(ab)d= .5vf² - 2

since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab)

10-.5vf² + 2 = 2vf² - 8
12 - .5vf² = 2vf² - 8
20 = 2.5vf²
vf² = 8

they both will have the same velocity
KE of block A= .5(4)(2.828²) = 16 J
KE of block B=.5(1)(2.828²) = 4 J</span>

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3 years ago

How was your "therapy" session with Eliza? Describe your experience with the therapy program.

VladimirAG [237]

I'm gonna need more context...

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3 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim

never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

$\text{Distance}=20\times 0.5=10\ m$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m$

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

$\text{Distance}=u\times 0.5=0.5u\ m$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0$

$u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s$

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0

3 years ago

Read 2 more answers

An object moves in simple harmonic motion with amplitude 11m and period 4 minutes. At time t = 0 minutes, its displacement d fro

Sergio039 [100]

Answer:

Explanation:

Angular velocity ω = 2π / T = 2 x 3 . 14 / (4 x 60 ) = .026 rad / s.

d = D Sin ( ωt + θ ) where D = amplitude = 11 m θ = initial phase.

-11 = 11 sin ( 0 + θ ) = sin θ = -1 , θ = - π /2

So, d = D Sin ( ωt - θ )

d = 11 Sin ( .026 t - π /2 ) is the required equation.

8 0

3 years ago

Determine the wavelengths for Potassium (violet, λ = 400 nm) and Strontium (red, λ = 700 nm) light emissions. Calculate the freq

TEA [102]

Answer:

For Potassium:

Frequency = 7.5 x 10¹⁴ Hz; E (energy) = 8.83 x 10⁻²¹ J

For Strontium:

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = 2.85 x 10⁻¹⁹ J

Explanation:

Wavelength is represented by λ, and Frequency is represented by ν .

E (energy) = hν = hc/λ, where ν = frequency; c = speed of light = 3 x 10⁸ m/s; 1 s-1 = 1 Hz

h = planck's constant = 6.62 x 10⁻³⁴ J.s; 1 nm = 10⁻⁹ m

1. Potassium λ (wavelength) = 400 nm, Frequency, ν is given by :

ν = c/λ = (3 x 10⁸ m/s) / 400 nm

= (3 x 10⁸ m/s) / 400 x 10⁻⁹ s-1

= 0.0075 x 10¹⁷s-1

= 7.5 x 10¹⁴ s-1

Frequency = 7.5 x 10¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (7.5 x 10¹⁴s-1)

E (energy) = 8.83 x 10⁻²¹ J

2. Strontium λ (wavelength) = 700 nm ,Frequency, ν is given by :

ν = c/λ = (3 x 10⁸ m/s) / 700 nm

= (3 x 10⁸ m/s) / 700 x 10⁻⁹s-1

= 0.00428571428 x 10¹⁷s-1

= 4.3 x 10¹⁴ s-1

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (4.3 x 0¹⁴s-1)

E (energy) = 2.85 x 10⁻¹⁹ J

4 0

3 years ago

Read 2 more answers