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gulaghasi [49]
3 years ago
12

Chef Jess made a cake with an area of 93 1/2 inches if the width of the cake was 8 1/2 inches what was the length of the cake

Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

L= 11

Step-by-step explanation:

Formula to find the length when you know the area:

L = A/W

So the equation for this one is:

L = 93 1/2 ÷ 8 1/2

Simplify:

L = 11

To be sure of your answer you multiply the L x W = A

11 x 8 1/2 = 93 1/2

Hope this helped : D

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A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
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Answer:

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Step-by-step explanation:

Given:

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The volume of paint needed

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                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

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                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

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                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

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