Answer:
40 mph
Step-by-step explanation:
To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:
168 = 0.05s^2 + 2.2s
0.05s^2 + 2.2s - 168 = 0
Using Bhaskara's formula: we have:
Delta = 2.2^2 + 4*0.05*168 = 38.44
sqrt(Delta) = 6.2
s1 = (-2.2 + 6.2)/0.1 = 40 mph
s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)
So the maximum speed of the car is 40 mph
10x=7
x=7/10, you could work backwards to find y if it asked
Answer: 12 times
Step-by-step explanation: 105 - 45 for initial fee is 60 then you divide that by 5 for 12
Section A) The AROC for Part A is 4.
h(x) = 4 * 1. 4 is your answer.
Section B) The AROC for Part B is 1.
h(x) = 4 * 1. 4 is your answer.
Part A: (Above)
Part B: There is no greater average change, both X's AROC is 4.
A.R.O.C: (Average Rate of Change)
I think this is right. Not 100% though
Answer:
21.25 m
Step-by-step explanation:
y = Ax² + Bx + C
Set the origin at the middle of the span so that the point (0, 0) is on the curve
0 = A(0)² + B(0) + C means C = 0
The points (200, 85) and (-200, 85) are on the curve
85 = A(200)² + B(200)
85 = A(-200)² + B(-200)
85 - 40000A - B(200) = 85 - 40000A + B(200)
- B(200) = B(200)
-400B = 0
B = 0
85 = A(200)²
A = 85/40000
y = 85x²/40000
y = 85(100)²/40000 = 21.25 m
