Answer:
9 people should get on stop 1.
Step-by-step explanation:
If i understood it correctly .
13 people on bus initially.
at first stop - 4 people get off . So 9 people should be on bus.
But few get in bus ( that is what is asked in the question - but it is not super clear to me)
after 2nd stop - there are 12 people on bus.
at 2nd stop 6 people got off.. so there were total of 18 on the bus
So if there were 9 people on bus stop by stop 1 .. so 9 people should have got in bus at stop 1 to make it equal to 18.
Only doubt i have is : if the question is asking how many got on the 2nd stop. also i was not clear what does this line means - At the first stop, four people get off and to get on.
Use an equation:
x^9/x^6=64
x^(9-6)=64
x^3=64
x=4
note that x^9 means "x to the power of 9", same with other ones
the number is 4.
Answer:
im just testing this but if you did that you would be slow as heck.
Step-by-step explanation:
17 minutes is decent so...
Answer:
10.5 %
<u>Skills needed: Financial Math Essentials</u>
Step-by-step explanation:
1) First, before getting started, let's assume the price of the product is 
. This variable will be used a lot throughout the problem ().
2) Marking a price above means increasing the price in order to make money off of the purchased product. When raising something by 
percent, the new price would be 
.
---> In this case, the price increased by 
percent.
This means that it would be: 
New price is: 
3) The shopkeeper is then offering a 
percent discount off of this marked price. When offering a 
percent discount price, the new price (with discount), expressed algebraically is: 
---> the expression above simplifies to 
In this case, 
, 
---> 
This means that , with discount, has been raised 
.
10.5 % is the profit percent
(The profit percent being the final marked up price - purchased price)
Answer: y=-3/1x+13
Step-by-step explanation: I just graphed the two points then found there slope and then I finished the line with the slope and then when I knew what was the y-intercept I finished the problem
