Question

One half a number increased by three is greater than zero or less than or equal to negative three

Answer 1

-3 is the answer to the question

Answer 2

Answer:

The required inequality for both the statement is: $\frac{1}{2} x+3>0$  and $\frac{1}{2}x+3\leq -3$

The solution for the inequalities are x>-6 and $x\leq -12$ respectively.

Step-by-step explanation:

Consider the provided information.

One half a number increased by three is greater than zero

Let the number is x.

Thus, the required inequality is:

$\frac{1}{2} x+3>0$

Or One half a number increased by three is less than or equal to negative three.

Thus, the required inequality is:

$\frac{1}{2}x+3\leq -3$

Now solve the above inequality for x.

$\frac{1}{2} x+3>0$  or  $\frac{1}{2}x+3\leq -3$

$\frac{1}{2} x>-3$  or  $\frac{1}{2}x\leq -3-3$

$x>-3\times 2$  or  $\frac{1}{2}x\leq -6$

$x>-6$  or  $x\leq -12$

Hence, the value of x is $x>-6$  or  $x\leq -12$