Answer:
The required inequality for both the statement is:
and ![\frac{1}{2}x+3\leq -3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%2B3%5Cleq%20-3)
The solution for the inequalities are x>-6 and
respectively.
Step-by-step explanation:
Consider the provided information.
One half a number increased by three is greater than zero
Let the number is x.
Thus, the required inequality is:
Or One half a number increased by three is less than or equal to negative three.
Thus, the required inequality is:
![\frac{1}{2}x+3\leq -3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%2B3%5Cleq%20-3)
Now solve the above inequality for x.
or ![\frac{1}{2}x+3\leq -3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%2B3%5Cleq%20-3)
or ![\frac{1}{2}x\leq -3-3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%5Cleq%20-3-3)
or ![\frac{1}{2}x\leq -6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%5Cleq%20-6)
or ![x\leq -12](https://tex.z-dn.net/?f=x%5Cleq%20-12)
Hence, the value of x is
or ![x\leq -12](https://tex.z-dn.net/?f=x%5Cleq%20-12)