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krok68 [10]
2 years ago
8

What is the solution set of the inequality below?

Mathematics
2 answers:
bogdanovich [222]2 years ago
4 0

Your answer is C

Step-by-step explanation:

Multiply -33 x 11

oksano4ka [1.4K]2 years ago
3 0
B. y less than 33 is the solution set .
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Justin and George bought some baked goods. Justin purchased 5 cookies for x dollars each and 4 doughnuts for y dollars each and
borishaifa [10]

The given statement 5x=4y=12 and x+6y=5 is true.

<u>Step-by-step explanation:</u>

The question comes from linear equations in two variables.

Here, two unknown variables represent a certain situation and their value can be obtained by solving both the given equations.

The cost of cookie is represented by the variable x and cost of doughnuts can be represented by the variable y.

The coefficient of each variable in the equation represent the quantity or the number of units of each baked good.

On comparing the given equations from the data provided in the question, the statement can be stated as true.

8 0
3 years ago
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liberstina [14]

Answer:

Similarly: yes

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3 years ago
Rafeal wants to know if there is a single transformation that will move trapezoid JKLM onto trapezoid PQRS Below
aliina [53]

A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.

Step-by-step explanation:

Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.

A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.

When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)  

8 0
3 years ago
7. A clothing trunk is 30 inches tall, 48 inches wide,
Vinvika [58]

Answer:

34,560 in^3

Step-by-step explanation:

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4 0
2 years ago
Help!!!!! Not the top one by the way..!
OverLord2011 [107]

Answer:

\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}

3 0
3 years ago
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