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Nataly [62]
2 years ago
13

F(x) = x^2-3 What is the average rate of change on the interval [-5, 2] ?

Mathematics
1 answer:
Mumz [18]2 years ago
7 0

Answer:

(-3).

Step-by-step explanation:

Over this interval, the change in the value of this function is:

f(-5) - f(2) = 22 - 1 = 21.

The corresponding change in the value of x:

(-5) - 2 = -7.

The average rate of change of function f over this interval is equal to the change in the function value divided by the corresponding change in x:

\begin{aligned}& (\text{average rate of change}) \\ =\; & \frac{(\text{change in function value})}{(\text{change in $x$})} \\ =\; & \frac{f(-5) - f(2)}{(-5) - 2} \\ =\; & \frac{22 - 1}{-7} \\ =\; & \frac{21}{-7} \\ =\; & -3\end{aligned}.

Thus, the average rate of change of f(x) = x^{2} - 3 over the interval [-5,\, 2] would be (-3).

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