Answer:
L = 10.64°
Step-by-step explanation:
From the given information:
In triangle JKL;
line k = 9.6 cm
line l = 2.7 cm; &
angle J = 43°
we are to find angle L = ???
We can use the sine rule to determine angle L:
i.e

Using Pythagoras rule to find j
i,e
j² = k² + l²
j² = 9.6²+ 2.7²
j² = 92.16 + 7.29
j² = 99.45

j = 9.97
∴



160 square inches
if the block is cut after it’s been painted, two sides with the same measurements don’t have glitter on them. you find the area of the one rectangle and multiply it by 2 as follows:
A = length • width
A = 10 • 8 = 80
area that needs to be covered = 80 • 2 = 160 square inches
Answer:
27 3/32
Step-by-step explanation:
Answer:

Step-by-step explanation:
we have

Find out the domain
we know that
The radicand must be greater than or equal to zero
so

The domain is the interval -----> [0,∞)
All real numbers greater than or equal to zero

Sorry what what is the question?