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3 years ago

What is the solution to the equation below? Round your answer to two decimal places. log6 x = 2.1

2 answers:

6 0

You just have to change the log form to exponential form.

log(b) x = y is the same and saying b^y = x

so 6^2.1 = x

x = 43.06

lyudmila [28]3 years ago

4 0

Answer:

The solution of the equation is 43.06.

Step-by-step explanation:

Consider the provided equation:

$log_6x = 2.1$

Consider the left side and apply the rule: $\quad \:a=\log _b\left(b^a\right)$

$2.1=\log _6\left(6^{2.1}\right)$

Substitute the value of 2.1 in provided equation.

$\log _6\left(x\right)=\log _6\left(6^{2.1}\right)$

$\mathrm{For\:}\log _6\left(x\right)=\log _6\left(6^{2.1}\right)\mathrm{,\:\quad solve\:}x=6^{2.1}$

$x=6^{2.1}$

$x=43.06}$

Hence, the solution of the equation is 43.06.

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Step-by-step explanation:

use formula of length of the diagonal of rectangle equal to d/rt2

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3 years ago

Can anyone help me with this?

Vika [28.1K]

Answer:

x = 51

Step-by-step explanation:

The figure shown is a pentagon

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Which means that 77 + 107 + 156 + 149 + x = 540

^ ( note that we just created an equation that we can

use to solve for x )

We then solve for x using that equation

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3 years ago

A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that

inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, $H_0$ : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, $H_1$ : p $\neq$ 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }$ ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

$\hat p$ = percentage of readers who own a particular make of car in a

sample of 220 = 0.30

n = sample size = 220

So, Test statistics = $\frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }$

= -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

3 0

3 years ago

6. trapezoid ABCD shown below, AB|| DC, overline BC perp overline DC and sides have lengths as shown (aDetermine the measure of

laila [671]

Answer:

a). ∠D = 56°

b). AD = √13

Step-by-step explanation:

(a) From the figure attached, ABCD is a trapezoid with parallel sides AB and CD. We have to find the measure of ∠D from the given figure.

From triangle ADE,

$tanD=\frac{AE}{DE}$