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Ostrovityanka [42]
2 years ago
8

the volume of a cylinder is 411π in^3. The height of the cylinder is 9 in. Calculate the diameter of the cylinder to the nearest

tenth of a centimeter.
Mathematics
1 answer:
EleoNora [17]2 years ago
8 0

Answer:

13.5 in, or 34.3 cm.

Step-by-step explanation:

First, use the formula volume = pi * r^2 * height- you have the volume, so just solve the equation 411pi = pi * 9 * r^2 for r, and you get that r = 6.75. Since diameter is equal to 2r, multiply 6.75 by 2 to get your answer of 13.5 inches. The questions asks for the diameter in centimeters though, which makes it 34.3 cm.

Hopefully this helps- let me know if you have any questions!

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Step-by-step explanation:

6 0
3 years ago
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
Samuel and Zander together have $392. Samuel has six times as much money as Zander. How much does each have? Please help! Quick
Shalnov [3]

Answer:

Samuel has $336 and Zander has $56

Step-by-step explanation:

Samuel = 6x because he has 6 times Zander

Zander = x

Together they have 392

6x + x = 392

7x = 392

Divide both sides by 7

x = 56

Samuel = 6 x 56 = 336

Zander = 56

336 + 56 = 392

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2 years ago
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Answer:

always true

Step-by-step explanation:

Given

2(x + 3) = 5x + 6 - 3x ← distribute left side

2x + 6 = 2x + 6

Since both sides are equal then any real value of x is a solution.

Thus the equation is always true

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2 years ago
How is the graph of y=(x-1)2-3 transformed to produce the graph of Y = 3(x+4)?,
liubo4ka [24]

Answer

3412

Step-by-step explanation:

7 0
2 years ago
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