Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
A) 950, 900, 1000
b) 1860, 1900, 2000
c) 200, 200, 0
d) 650, 600, 1000
e) 19900, 19900, 20000
Answer:
The cost of wasted nitric acid is $187.02
Step-by-step explanation:
Since it is given that specific gravity of Nitric Acid is 1.42 Thus the density of nitric acid is
Now from the basic relation of mass volume and density we have
Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams
Thus the volume of nitric acid is
Now we know that 1000 cubic centimeters euals 1 litrer
Thus the calculated volume in liters is
Thus the cost of acid spilled equals
Answer: 400 because 40 multiplied by ten equals 400 hundred, so basically it's just 40 multiplied by 10.
Answer: a) = 10
b) = 16
Step-by-step explanation:
a) as x = 5 so putting the value of x in given equation
5 multiplied by 2 is equal to 10
b) Putting value of x in given equation
= (5 + 3) 2
According to BODMAS solve the brackets first
= 8 x 2
= 16
