Question

The lengths of the diagonals of a rhombus are 4x and 8x. What algebraic expression gives the perimeter of the rhombus?

Answer 1

Answer:

Approximately 17.88x or $8x\sqrt{5}$

Step-by-step explanation:

Use pythagorean formula. In a rhombus the diagonals bisect each other and they are perpendicular, so you could have a right triangle with legs of 2x and 4x, the hypoteneuse would then be $\sqrt{(2x)^{2} +(4x)^{2} }= \sqrt{4x^{2} +16x^{2}}$ which is approximately 4.47x. In a rhombus all 4 sides are the same, so multiply that by 4 and you get the perimeter. 4(4.47x) = 17.88x  or if you simplify the radical instead it's $8x\sqrt{5}$