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natta225 [31]
3 years ago
12

Help? Anything can help I’m in a rush

Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer: A vertical line from (-5 , 4 ) to (5 , 4)

Step-by-step explanation: The y axis is the vertical  one. Go up 4 and draw a line connecting all the points with 4 in the coordinates.

Hope that helps :)

DaniilM [7]3 years ago
7 0

Answer:

Step-by-step explanation:

go up 4 lines on the y-axis then draw a straight line from left to right on y=4

I don't know if you can see the picture, but I drew a line on the picture you provided...

Please 5 stars if correct!!!

I hope this helps

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HELP PLS! I CAN’T FAIL PRE-ALGEBRA!
Liono4ka [1.6K]

Answer:

Q1.  2 - 5/ 8 - 0 = -3/8

Q2.  1- (-1)/6-2 = 2/4 simplified as 1/2

Q3.  (-5)- (-2)/ (-1)- (-3) = -3/2

Use a ruler to help you graph a line whose slope is 1/3. Label this line “a”

*Answer- 1/3 is being shown for rise/run (Rise over Run, 1 being rise and 3 being run). this means that you go up one and right 3.

Step-by-step explanation:

y2-y1 *over* x2- x1. Also if you can simplify the end fraction do it but if not then leav it as it is. This is the equation that I used for the first 3 problems. Also I didnt quit understand the 1st word problem sorry! I hope this helps :v

8 0
2 years ago
3. x + 4y = 30<br> x - 2y = 0
kolbaska11 [484]

Answer:

Step-by-step explanation:

Given that:

x + 4y = 30

x - 2y = 0

Subtracting both equations:

6y = 30

y = 30/6

y = 5

Putting in above equation

x + 4(5) = 30

x + 20 = 30

x = 10

i hope it will help you

5 0
3 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
Joe has fraction 5 over 6 pound of bird seed. He needs Fraction 1 over 3. pound to feed the birds daily. Which of the rectangle
Studentka2010 [4]
I divided the two fractions & drew a model.

\frac{5}{6}/ \frac{1}{3} = 2.5

So we know that the bird seed will last 2.5 days.

Knowing this, we can go with:

B. Rectangle model divided into six equal sections, five sections are labeled five-sixths and two sections are labeled one-third, equaling two and one-half days.

Let me know if you find any problems with my answer.


9 0
3 years ago
1 /2 + 3/ 4 ÷ 1/3 –1( they are fractions)
marysya [2.9K]

Answer:

2 2/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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