The standard position of a function is y = ax^n + bx^n-1 + ... k where a, b and k are all constants. In this case, the problem gives
<span>y = − one over two (x − 2)2 − 2
Translating numerically,
y = [-1/2(x-2)^2 ] -2
2(x-2)^2 y = -1 -2(2*(x-2)^2)
</span>2(x-2)^2 y= -1 -4(x^2-4x+4)
y = (-4x^2 + 16x -17) /(2(x-2)^2)
Remember that parallel lines have the same slope.
y=3/7x+11 (in slope intercept form already)
-3x+7y=13 (standard form)
Add 3x to both sides, giving you 7y=3x+13, divide by 7 on both sides, giving
y=3/7x+13/7
Since both equations' slopes' are the same, their graphs will be parallel.
You are correct. you are looking for a negative slope. y=mx+b where m is the slope.
1/70=+
-83/-27 = 83/27=+
8=+
-6=-
Let me know if you have questions.
Answer: The correct option is D, i.e., 5.
Explanation:
Dilation is defined as the enlargement or compression of a figure along the center of dilation according to the scale factor k.
If k>1 then it shows the enlargement and if 0<k<1 then it shows the compression.
If k is negative the image and preimage lies on the opposite sides of center of dilation.
The image and preimage are similar to each other and the sides are in the proportion of k.
In the given figure the length of side CA is 4 unit.
The image of CA is CA' and its length is,
Since the given figure shows the enlargement, so k>1.
Therefore, the value of k is 5 and D is the correct option.
Answer:
It's going to be B and E because it's in the hundreds place not in the tens or whole