Answer:
0.25 (inches?)
Step-by-step explanation:
the equation is:
y=mx+b
y is the length of her hair, the dependent variable, the outcome
m is the slope, which is in this case the growth of her hair in a month
x is the independent variable, or the number of months
b is how long her hair is to start with, which is 12 in
we are looking for m, which is the growth of her hair per month, which is given as 0.25 inches, so that would be the answer
Addition: 70 + 80 = 150. You round 65 up because the ones digit is greater than and the same with 77.
Multiplication: Round up since both ones digits are bigger than 5. 70 x 80= 5600.
Answer:
a
The probability that the selected joint was judged to be defective by neither of the two inspectors is 
b
The probability that the selected joint was judged to be defective by inspector B but not by inspector A is 
Step-by-step explanation:
From the question we are told that
The sample size is 
The number of outcome for inspector A is 
The number of outcome for inspector B is 
The number of joints judged defective by both inspector is 
The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

Now

substituting values

So


the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

Now

substituting values

So

