Answer:
i think B.
Step-by-step explanation:
Hope this helps :p
The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.
How many are there because there is no pic
Answer:
2x² +7x - 4
Step-by-step explanation:
(2x-1)(x+4)
2x² + 8x - x - 4
simplify:
2x² +7x - 4